INDOOR
POOL AIR CHANGE CALCULATION
Evaporation from the wave pool and spa areas of the water park,
combined with people gain, created the demand for incoming air
to absorb 944 lbs/hr of water to maintain proper conditions.
Once it was determined that condensation was not a concern, the
next step was to figure out exactly how much moisture would be
generated internally and need to be removed. To calculate the
amount of water that would evaporate due to the various pools
and people, the following equation was used:
(Equation 3) wp = 0.1A x (pw – pa) x Fa
Where:
wp = Evaporated moisture (lb/hr)
A = Area, (sq ft)
pw = Saturation pressure, evaporated water vapor, (in. of mercury)
pa = Partial pressure, water vapor, in ambient air, (in. of mercury)
Fa = Activity factor, (from ASHRAE 1999 Table)
In the case of the Alaska water park, the following data was
used: Saturated vapor pressure, spa: ps = 2.11661 in. Hg. at 103°;
saturated vapor pressure, wave pool: ps = 2.17608 in. Hg. at 84°;
saturated vapor pressure, air: pa = 1.25388 08 in. Hg. at 86°;
room air dewpoint = 74.5°, Þ ps =0.855
Then for each of the components, the contributed moisture was
calculated as follows:
Vapor produced by the spa:
wp = 0.1 x 354 x (2.11661-0.855) x 1.0 = 44.66 lb/hr
Vapor produced by the wave pools:
wp = 0.1 x 15,335 sq ft x (1.17608 – 0.855) x 1.5 = 738.6
lb/hr
People Gain
wp = 0.325 lb/hr x person x 200 occupants = 65 lb/hr
Total vapor produced = 44.66 + 738.6 + 65 = 944 lbs/hr
This means that the incoming air must be capable of absorbing
944 lbs/hr water, without exceeding the 86°, 60% rh indoor
conditions recommended by ASHRAE1.
Having defined the amount of moisture that needed to be removed
from the atmosphere, the next step was to define the method of
calculating just how much air would be required to accomplish
this.
From the psychrometric chart:
Indoor moisture content at 86°, 60% rh = 0.016 lb/lb of air
Outdoor moisture content at 71°, 60° wb = 0.086 lb/lb
of air
The available humidity pick-up between outside ambient conditions
in the summer and indoor ambient conditions is the difference
between these two values = 0.0074 lb/lb of air.
Density of air at standard temperature and pressure = 13.5 cu
ft/lb
D moisture = 0.0074-13.5 = 0.000548 lb/cu ft of air
In order to calculate the quantity of air necessary to absorb
944 lb/hr of moisture, the following calculation was performed:
(Equation 4) cfm = 944 lbs/hr/0.000548 lb/cu ft/ 60 min/hr =
28,710 cfm
As this calculation was performed using data from the peak design
condition for summer, (when incoming air would be at peak humidity,
and therefore have the least absorption capability), the 28,710
cfm represents the maximum outside air needed for dehumidification.
It should be noted that in the winter, a mere 14,000 cfm of outside
air is adequate for fully dehumidifying the space; there is very
little water vapor in the air at temperatures below ing.
. Another special concern was avoiding stratification of heat
and humidity inside the 50-ft tall structure. To keep the hot
air flowing throughout, the engineering solution was to supply
most of the air via a below-floor plenum (Figure 1). As this was
already excavated volume, with one wall being the foundation itself
and the other the vertical side of the lazy river, using it as
a plenum was a creative idea, which did not add any construction
costs. This use of an underground concrete supply air plenum gave
the water park a clean, uncluttered look, delivering hot air that
migrates up to the return air grilles mounted high at the roof
peak.
In essence, the airflow creates a very efficient delivery pattern,
one that minimizes stratification and reduces pockets of humidity
in the space. Any water that splashes from the floor grilles is
collected in sumps and pumped out to avoid standing puddles, which
could create a health hazard.
One constant feature to be found at any great water park is the
“lazy river.” H2Oasis has its own lazy river called
the Never Ending River. The water stream flows at 5 miles per
hour, in a channel 575-ft long, along the perimeter of the 40,500-sq-ft
building. H2Oasis uses the Never Ending River to promote fitness
and fun together, by offering a program called Riverwalk. The
program allows guests to exercise against the current of the Never
Ending River. More than 200,000 gal of water are filtered for
the Never Ending River everyday.
Elsewhere, the water park’s wave pool reaches a depth of
6 ft, sloping to 1 ft at the shallow end. This feature can generate
up to 4-ft waves. The shallow part of the pool has a “mushroom”
water drop; the mushroom rains down water from its brim.
Another special feature of H2Oasis is the children’s lagoon.
What makes this lagoon unique is the Sea Dragon Pirate Ship. This
pirate ship consists of six water cannons, four on the ship and
two on the “beach.” The pirate ship extends 40-ft
in length, inside a 12-in. deep pool. There are seven slides on
the pirate ship for children to play on. About 400 gpm of water
race through the ship.
After years of planning and construction, Alaska has its very
own water park. Many people were skeptical of the idea that a
water park could be sustained, let alone the technical challenges
of building one. Numerous people inside and outside the state
of Alaska pulled together to build one of the most unique water
parks in the world, making H2Oasis the fifth largest indoor water
park in the United States.
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